3g of dry ice was added to 20g of water at 26^oC in a beaker of negligible heat capacity. After the ice had all melted,...

      

3g of dry ice was added to 20g of water at 26^oC in a beaker of negligible heat capacity. After the ice had all melted, the temperature of water was found to be 12C. Find the specific latent heat of fusion of ice. Take the s.h.c of water =4200JKg-1K-1

  

Answers


Moraa
0.1*4200*(26-11) = (0.03*lf) + (0.03*4200*11)
6300=0.03lf + 737.2
Lf=5560.8/0.03 = 3.4755 * 25JKg-1
Moraa orina answered the question on April 10, 2018 at 18:00


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